2.3 Higher Order Derivatives by RHO Flashcards
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| 7565124141 | 24x | Given f(x) = x⁴-5x²+7, find the third derivative. | 0 | |
| 7565401486 | -120x | Given y = -5x⁴, find the third derivative. | 1 | |
| 7565455615 | -60x² | Given y = -5x⁴, find the second derivative. | 2 | |
| 7565405892 | 180x² | Given y = 3x⁵ - 2x, find the third derivative. | 3 | |
| 7565409771 | -12 + 240/x⁶ | Given y = -2x³ - 4x⁻³, find the third derivative. | 4 | |
| 7565446467 | -12 - 48/x⁵ | Given y = -2x³ - 4x⁻³, find the second derivative. | 5 | |
| 7565432753 | 24x² + 24x + 6 | Given y = 2x⁴ + 4x³ + 3x², find the second derivative | 6 | |
| 7565426534 | 96x | Given y = 4x⁴ + x² - 5x, find the third derivative. | 7 | |
| 7565857098 | 4/x³+60/x⁶ | Given y = 2/x + 3/x⁴, find the second derivative | 8 | |
| 7565864073 | -12/x⁴ - 360/x⁷ | Given y = 2/x + 3/x⁴, find the third derivative | 9 | |
| 7565888976 | (42/25)x^(-4/5) | Given y=7x^(6/5), find the second derivative | 10 | |
| 7566023175 | (84/25)x^(-3/5) | Given y=6x^(7/5), find the second derivative | 11 | |
| 7565905215 | 24x - 18 | Given y = 4x³ - 9x²+6, find the second derivative | 12 | |
| 7565909865 | -sin(x) + 2 | Given y = sin(x) + x², find the second derivative. | 13 | |
| 7565914682 | -cos(x) + 2 | Given y = cos(x) + x², find the second derivative. | 14 | |
| 7565916537 | -cos(x) | Given y = sin(x) + x², find the third derivative. | 15 | |
| 7565924500 | 29 | s(t) = 3t² + 5t + 2 describes a particle's motion with units in meters. Find the instantaneous velocity at t = 4 seconds. | 16 | |
| 7565928754 | 6 | s(t) = 3t² + 5t + 2 describes a particle's motion with units in meters. Find the instantaneous acceleration at t = 4 seconds. | 17 | |
| 7565932392 | 18 | A particle moves along a path with its position s(t) = t² - 6t + 8 meters. When does the velocity equal 30 m/s? | 18 | |
| 7565937576 | 3 | A particle moves along a path with its position s(t) = t² - 6t + 8 meters. When is the particle at rest? | 19 | |
| 7565942335 | 100 | If the position of a particle is given by s(t)=100−16t², find the position of the particle when the velocity is zero. | 20 | |
| 7565956685 | 194 | The vertical position of a ball is given by s(t)=−16t²+96t+50 feet. What is the maximum height the ball will reach? | 21 | |
| 7565964516 | -96 | A ball with position function s(t)=−16t² + v₀t+s₀ is thrown straight upward from the ground with an initial velocity of 96 ft/sec. Find its velocity when it hits the ground. | 22 |