AP Statistics Chapter 5 Flashcards
Aligned to The Practice of Statistics (Starnes, Tabor, Yates, Moore) 5th edition
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| 6749842659 | complementary events | two disjoint events that together make up the entire sample space | 0 | |
| 6749842660 | P(at least 1) | 1- P(none) | 1 | |
| 6749842661 | mutually exclusive events (disjoint events) | events that can't happen at the same time | 2 | |
| 6749842662 | Interpretation of A ∩ B | A intersect B; the outcomes that are in A and that are also in B | 3 | |
| 6753981077 | Formula for the probability of two INDEPENDENT events, A and B, occurring | P(A) x P(B) | 4 | |
| 6753994510 | Formula for the probability of two events, A and B, occurring; events DO NOT need to be INDEPENDENT | P(A) x P(B | A) | 5 | |
| 6749842667 | Interpretation of A ∪ B | A union B; the outcomes that are in A or B (or both) | 6 | |
| 6753940422 | Formula for the probability of event A or event B occurring | P(A) + P(B) - P(A and B) | 7 | |
| 6749842664 | The Law of Large Numbers | As the number of trails increases, the proportion of times a specific outcome occurs approaches a the true probability of the event | 8 | |
| 6749842669 | outcome | the possible result of a situation or experiment | 9 | |
| 6749842670 | event | a single outcome or a group of outcomes | 10 | |
| 6749842671 | sample space | the set of all possible outcomes | 11 | |
| 6749842672 | probability | the numerical value from 0 to 1 that describes the proportion of times the outcome would occur in a very long series of repetitions P(event) = (number of favorable outcomes) ÷ (number of possible outcomes) | 12 | |
| 6749842665 | trial | in probability, a single repetition or observation of an experiment | 13 | |
| 6749842666 | probability model or probability distribution | identifies all possible outcomes and the corresponding probability of each possible outcome | 14 | |
| 6749842668 | conditional probability, P(A | B) | The probability that A occurs, given that B has occurred | 15 | |
| 6754047758 | Formula for conditional probability "B given A" | P(B | A) = P(A n B) / P(A) | 16 | |
| 6754012922 | Independent Events | If the occurrence of one event has no effect on the change that other event will happen | 17 | |
| 6754031125 | Numerical way to show 2 events are independent | P(A) = P(A | B) AND P(B) = P(B | A) | 18 |