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Gibb's Free Energy

Gibbs free energy - free energy

  • G < 0 >> spontaneous reaction
  • G = 0 >> reaction at equilibrium
  • G > 0 >> nonspontaneous reaction (reverse reaction could be spontaneous)
  • G = H - TS
  • DG =DH - T (DS)
  • always negative when H negative, S positive
  • always positive when H positive, S negative

Find the conditions surrounding the stretching of a rubber band.  

  • needs energy to stretch rubber band
    • DG is positive (nonspontaneous event)
  • rubber band becomes more orderly when stretched
    • DS is negative
  • release of heat when rubber band is stretched
    • DH is negative

Calculate DG (in kJ) for Mg(s) + 1/2O2 >> MgO(s) at 300K  

  • Given:
    • DHf of MgO = -601.8
    • DS° of Mg(s) = 32.7 J
    • DS° of O2 = 205 J
    • DS° of MgO(s) = 26.9 J
  • DS = 26.9 - (1/2 x 205 + 32.7) = -108.3 J = -0.1083 kJ
  • DG = -601.8 - 300(-0.1083) = -569.31 kJ

nonstandard free energy - value differs from standard value at different conditions

  • DG = G° + RT lnQ
    • R = constant (8.314 J/mol-K)
    • Q = equilibrium constant
  • at equilibrium,G° = -RT lnKeq
  • G < 0 >> Keq > 1
  • G = 0 >> Keq = 1
  • G > 0 >> Keq< 1

Calculate the Keq for 2NO2 (g) >> N2O4 (g) at 25°C  

  • Given:
    • DHf of NO2 = 33.84 kJ
    • DHf of N2O4 = 9.66 kJ
    • DS° of NO2 = 240.4 J
    • DS° of N2O4 = 304.3 J
    • R = 8.314
  • DS = 304.3 - 2(240.4) = -176.5 J = -0.1765 kJ
  • DH = 9.66 - 2(33.84) = -58.02 kJ
  • DG = -58.02 - (273+25)( -0.1765) = -5.423 kJ = -5423 J
  • DG = -RT lnKeq
  • -5423 = -(8.314)(298) lnKeq
  • lnKeq = 2.1888
  • Keq = e2.1888 = 8.92
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