equilibrium in reactions - when forward/reverse reactions occur at same rate
- ratio of partial pressures, concentrations equals constant
- pressures no longer change
- reaction continues to occur, but ratio stays the same (no net change)
- can be reached from either direction
Haber Process - synthesizing ammonia from hydrogen/nitrogen
- world’s main source for fixed nitrogen
- N2 + 3H2 <<>> 2NH3
equilibrium constant - only changed by temperature, not by reaction mechanism
- for reaction aA + bB <<>> cC + dD
- Keq = (C concentration)c(D concentration)d / (A concentration)a(B concentration)b
- value determined by coefficients in chemical equation
- value greater than 1 >> equilibrium towards product side
- value less than 1 >> equilibrium towards reactant side
- for any reaction, constant equal to reciprocal of constant for reverse reaction
- constant raised to power equal to number by which reaction is multiplied
- constants multiplied together for net reactions involving 2+ steps
- do not include pure solids, pure liquids, or solvents in finding constant
For the reaction CaCo3(s) >> CaO(s) + CO2(g), K = 0.0108. Find the equilibrium weight of CO2 if 2g of CaCo3, 2g of CaO, and 0.5g of CO2 were placed in a 1 liter flask.
- don't take account of solids in the reaction
- K = [CO2] = 0.0108 mol
- 0.0108 mol = grams CO2 / CO2 molar mass
- 0.0108 = grams CO2 / (12 + 16 x 2)
- grams CO2 = 0.0108 (44)
- 0.475 g
At equilibrium for the reaction 2NO(g) + Cl2(g) >> 2NOCl, K = 51. If [NOCl] = 0.10 and [Cl2] = 0.20, find [NO]
- K = 51 = [NOCl]2 / ([NO]2[Cl2])
- [NO]2 = 0.12 / 0.2 / 51 = 0.00098
- [NO] = 0.031