does anyone know a step by step method of doing limits? any help would be appreciated!
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It depends on the problem. If just plugging in the number gets you an indefinite (1/0, etc.), you'll need to find a way to cancel out the denominator so that you can a real number.
You can try factoring out the limit on top and on the bottom. If something cancels out, then try plugging the limit into it and get a number. Or just looking at the exponents, if the first variable's exponent is higher in the numerator than the one in the denominator, then the limit is approaching infinity. If the first variable's exponent in the denominator is bigger, than the limit is approaching zero.
"If electricity comes from electrons, does morality come from morons?"
Oh, yeah. I forgot about the infinity ones.
Plug in a number really close to the number you are trying to find. For instance, if it is 2, plug in 2.001 if it is from the right, or 1.999 if it is from the left. You also should factor the equation as much as possible. Follow simplyfantabulis's rules only for limits approaching + or- infinity.
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-plug in numbers close to the actual number (i.e. instead of 3, something like 2,9999 ir 3.0001)
-divide the numerator and denominator by the highest power in the fraction
-L'Hopital's rule
-graphs/TI
-factor
Can anyone explain the sqeeuze theorm for me? The bisection method?
This of course is in relation with limits.
BioHazard;91886 wrote:Can anyone explain the sqeeuze theorm for me? The bisection method?
This of course is in relation with limits.
A problem would probably be: find the lim, x goes to A, of F(X), and then it will give you an inequality with F(X) in the middle with two equations on the side.
So u have to take the limits of the other two functions.
If these two are equal, then F(X) also has to have the same limit because it is in between the two.
This is basically the Squeeze Theorem.
Hope this helps
What is L'opital's Rule?
and the bisection method?