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14372376692First Law of ThermodynamicsEnergy lost by one object must be gained by another object0
14372376693How heat can be applied in a handshakeHeat is transferred from hotter hand to colder hand1
14372376694Exothermic reactionProduct bonds are stronger Heat is a product (released) ΔH is negative2
14372376695Endothermic reactionReactant bonds are stronger Heat is a reactant ΔH is positive3
14372376703Equation for change in enthalpyq = mCΔT4
14372376704What is the specific heat needed for 2.98 g of aluminum (specific heat of 0.98 J/g°C) to be heated from 21.6°C to 29.8°C?q = 2.98 g * (0.98 J/g°C) * 8.2°C = 24 J5
14372376705High specific heatHeats/cools slowly (Takes a lot of energy to change temperature)6
14372376706Low specific heatHeats/cools quickly (Only a small amount of energy needed to change temperature)7
14372376707A piece of copper is heated to a temperature of 91°C and placed into 125 g of water at 25°C (C of copper = 0.39 J/g°C). What mass of copper was used?q(H2O) = 125 g * 4.18 J/g°C * (27-25)°C = 1000 J 1000 J = m * 0.39 J/g°C * (91-27)°C m = 40 g8
14372376708What is the specific heat of zirconium if 2514 J is required to raise 298 g of the substance from 23.0°C to 52.8°C? What is it's molar heat capacity?2514 J = 298 g * (C) * 29.8°C C = 0.283 J/g°C * (91.224 g/mol) = 25.8 J/mol9
143723767091.40 g of wax (C25H52) is burned over 400 g of water. When burned, the temperature of the water goes from 25°C to 76°C. Find the heat of combustion per gram AND per mole of wax.q = 400 g * (4.18 J/g°C) * 51°C = 85000 J 1.40 g * (1 mol / 355.07 g) = 0.00394 mol 85 kJ / 1.40 g = -61 kJ/g 85 kJ / 0.00394 mol = -22000 kJ/mol10
14372376710Ethanol is combusted in the air, with the ΔH of the reaction being -1367 kJ/mol ethanol. How much heat is released when 3.88 g of ethanol is burned in excess oxygen?C2H5OH + 3O2 → 2CO2 + 3H2O 3.88 g C2H5OH * (1 mol C2H5OH/46.06904 g) * (1367 kJ/1 mol) = -115 kJ11
14372376711How much heat is released when 12.4 g of ethanol react with 22.3 g O2?12.4 g C2H5OH * (1 mol C2H5OH/46.06904 g) = 0.269 mol C2H5OH 22.3 g O2 * (1 mol O2/31.9988 g O2) * (1367 kJ/3 mol O2) = -318 kJ12
14372376712Hess's Lawthe overall enthalpy change in a reaction is equal to the sum of enthalpy changes for the individual steps in the process13
14372376725FeO(s) + CO2(g) → Fe(s) + CO2(g) ΔH = ?14
14372376726Acetylene is combusted in the air. Find the ΔH° of the overall reaction from: H2(g) + 1/2O2(g) → H2O(l): ΔH° = -285.8 kJ 2C(s) + H2(g) → C2H2(g): ΔH° = +226.7 kJ C(s) + O2(g) → CO2(g): ΔH° = -393.5 kJ15
14372376713Heat of formationMust come from its ELEMENTS16
14372376727Find the heat of formation for the following reaction: 4NH3(g) + 5O2(g) → 4NO(g) + 6H2O(g)17
14372376728Find the standard heat of formation of hexane (C6H14) given the overall heat of combustion is -4141 kJ/mol18
14372376729Draw and label a heating/cooling curve19
14372376730Calculate the total heat energy in Joules needed to convert 20 g of substance X from -10°C to 70°C given the following: Specific heat (C) of solid phase = 2.0 J/g°C Melting point = 12°C Heat of fusion = 0.232 kJ/mol Specific heat (C) of liquid phase = 5.0 J/g°C Boiling point = 63°C Heat of vaporization = 12000 J/g Specific heat (C) of vapor phase = 1.0 J/g°C20
14372376714EntropyA measure of disorder or randomness.21
14372376715Activation energythe minimum amount of energy required to start a chemical reaction22
14372376716Heat capacitythe amount of heat needed to increase the temperature of an object exactly 1°C23
14372376717Open systemA system in which matter can enter from or escape to the surroundings.24
14372376718Closed systemA system in which no matter is allowed to enter or leave25
14372376719State functiona property of the system that changes independently of its pathway26
14372376720Enthalpy of fusionthe enthalpy change that occurs to melt a solid at its melting point or freeze at its freezing point27
14372376721Enthalpy of vaporizationthe amount of energy absorbed as heat when a specified amount of a substance vaporizes at constant pressure28

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