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| 7273272072 | AP | Advanced Placement. |  | 0 |
| 7273272703 | Physics | The study of matter and energy. A branch of science that looks at the nature and properties of matter and energy. |  | 1 |
| 7355921123 | Distance | The length of a path between two points. How far an object moves. |  | 2 |
| 7355926973 | cm | Centimeter | 3 | |
| 7355926972 | Height | The measurement associated with an object's top-to-bottom dimension. | 4 | |
| 7355936738 | sin | Sine, or opposite over hypotenuse. y | 5 | |
| 7355967037 | Degree | Unit that temperature is measured in. Unit that measure angles. | 6 | |
| 7355974361 | s/m | Seconds per meter. | 7 | |
| 7355979743 | s | Second | 8 | |
| 7355983570 | m | Meter | 9 | |
| 7355986599 | m/s | Meters per second. Speed | 10 | |
| 7355992718 | Average Velocity | The total displacement divided by the time interval during which the displacement occurred. The ratio of the displacement vector over the change in time. |  | 11 |
| 7356006278 | Average | Mean Returns the average (Arithmetic Means) of its arguments. |  | 12 |
| 7356014746 | Velocity | Speed in a given direction. The speed of an object in a particular direction. |  | 13 |
| 7356014513 | Constant Velocity | Constant speed and direction. When an object travels the same distance every second. |  | 14 |
| 7356026510 | i | Initial | 15 | |
| 7356032380 | f | Final | 16 | |
| 7356036257 | d | Distance | 17 | |
| 7356040922 | t | Time | 18 | |
| 7356048867 | a | Acceleration | 19 | |
| 7356059448 | av | Average | 20 | |
| 7356077038 | When is a linear line at the same position as a curve? | When the linear line and curve meet. | 21 | |
| 7356083447 | When is a linear line at the same speed as a curve? | When the linear line is tangent to the curve. | 22 | |
| 7356121028 | Concepts | Displacement, position, and distance. |  | 23 |
| 7356133128 | Displacement's Symbol | Right arrow over (Change in x) | 24 | |
| 7356141104 | Right Arrow | Vector | 25 | |
| 7356144405 | Delta | Triangle meaning change. | 26 | |
| 7356150572 | x | Horizontal and usually labeled as time. |  | 27 |
| 7356178293 | Another Symbol Meaning the Same thing as Right Arrow Over Delta x | Right arrow over Delta d | 28 | |
| 7356186177 | Position's Symbol | Right arrow over d or right arrow over x | 29 | |
| 7356195217 | Right Arrow Over d and Right Arrow Over x | Location from origin. | 30 | |
| 7356198988 | Distance's Symbol | d or x | 31 | |
| 7356203755 | d and x | Length | 32 | |
| 7356210785 | Right Arrow Over (Change in x | Right arrow over x final - right arrow over x initial | 33 | |
| 7356228265 | Right Arrow Over x | Distance from origin. | 34 | |
| 7356233396 | Rate | Some quantity divided by time. A ratio that compares two quantities measured in different units. |  | 35 |
| 7356241660 | Velocity's Symbol | Right arrow over v | 36 | |
| 7356250631 | Position | Changes and is the location of an object. A place where someone or something is located or has been put. | 37 | |
| 7356268416 | Acceleration's Symbol | Right arrow over a | 38 | |
| 7356274184 | Acceleration | The rate at which velocity is changing. Change in velocity divided by the time it takes for the change to occur. |  | 39 |
| 7356313548 | Right Arrow Over a | (Right arrow over (Change in v)) over (Change in t) | 40 | |
| 7356329383 | Right Arrow Over Delta v | Change in velocity. | 41 | |
| 7356331088 | Delta t | Change in time. t Final - t Initial | 42 | |
| 7356338603 | m/s^2 | m/s/s Meters per second per second. |  | 43 |
| 7422962203 | 2.0 m/s^2 | 2.0 m/s/s The object gains 2.0 m/s of speed per second. | 44 | |
| 7422984712 | v Final | v initial + at | 45 | |
| 7423009210 | (v Final)^2 | (v initial)^2 + (2a(Change in x)) | 46 | |
| 7423028397 | Instantaneous | Happening immediately. Done in an instant; immediate. |  | 47 |
| 7423077634 | Instantaneous Velocity | At some instant in time. The speed and direction of an object at a particular instant. |  | 48 |
| 7423101944 | Slope | v average The steepness of a line on a graph. |  | 49 |
| 7423104869 | Slopes | Instantaneous velocities. A slanted surface. | 50 | |
| 7423115457 | tan | Tangent y/x |  | 51 |
| 7423121326 | d(t) | Distance over time. | 52 | |
| 7423132965 | Move Along Curve for... | Slope | 53 | |
| 7423138364 | Position Graph has... | Time as x-axis label. | 54 | |
| 7423146979 | x-Axis | The horizontal number line on the graph. The horizontal axis of the coordinate plane. | 55 | |
| 7423204312 | y-Axis | The vertical axis on a coordinate plane. The vertical number line on the graph. | 56 | |
| 7423214090 | v Subscript x | v subscript x(0) + (a subscript x)t | 57 | |
| 7423237569 | d Final | d initial +(v initial)t + .5a(t^2) | 58 | |
| 7423251435 | (v Subscript x)^2 | (v subscript x(0))^2 + 2(a subscript x)(Change in x) | 59 | |
| 7423288978 | v Subscript av | .5(v initial + v final) x over t | 60 | |
| 7423301189 | x Over t | .5(v initial + v final) | 61 | |
| 7423342653 | In Projectile Motion, v Initial is the Opposite of... | v final | 62 | |
| 7423354754 | sin(Theta) | (v subscript y initial) over v initial | 63 | |
| 7423354755 | cos | Cosign adj/hyp |  | 64 |
| 7423370433 | cos(Theta) | (v subscript x initial) over v initial | 65 | |
| 7423374491 | tan(Theta) | (v subscript y) over (v subscript x) | 66 | |
| 7423411778 | Angle | Measured in degrees. A figure formed by two rays with a common endpoint. |  | 67 |
| 7423416760 | psi | Pounds per square inch of pressure. Ψ |  | 68 |
| 7423432628 | Speed | m/s Distance/Time | | 69 |
| 7423438908 | h | Height | 70 | |
| 7423446334 | y Final | y initial + (v subscript y initial)t + .5gt^2 | 71 | |
| 7423461412 | Theta | Angle measure. Θ | 72 | |
| 7423491154 | p | Pressure and pulse. | 73 | |
| 7423503316 | P | Pressure, Phosphorus and pulse. | 74 | |
| 7423519387 | g | Gravity -9.8 m/s^2 | 75 | |
| 7423530531 | x Final | x initial + (v initial)t + .5a(t^2) |  | 76 |
| 7423568502 | Absolute Value of (Right Arrow Over F Subscript f) | Greater than or equal to the coefficient of friction times absolute value of (right arrow over F subscript n) | 77 | |
| 7423632377 | F | Force, Fluorine, Fahrenheit, Foxtrot, and female. | 78 | |
| 7423669013 | n | Number Nano | 79 | |
| 7423658879 | a Subscript c | v^2 over r | 80 | |
| 7423682182 | r | Radius | 81 | |
| 7423695390 | Right Arrow Over p | m times right arrow over v | 82 | |
| 7423708223 | Delta Right Arrow Over p | Right arrow over F times (Change in t) | 83 | |
| 7462099397 | K | .5m(v^2) Potassium | 84 | |
| 7462152019 | Change in E | W Change in energy. | 85 | |
| 7462166691 | W | F parallel to d | 86 | |
| 7462196574 | F Parallel to d | Fdcos(Theta) |  | 87 |
| 7462206135 | Special W | Special W(0) + at | 88 | |
| 7462222309 | Special T | Torque r perpendicular to F | 89 | |
| 7462262970 | r Perpendicular to F | rFsin(Theta) | 90 | |
| 7462269376 | L | I times Special W Liter |  | 91 |
| 7462275718 | Change in L | Special T times (Change in t) | 92 | |
| 7462289641 | Absolute Value of (Right Arrow Over F Subscript s) | k times absolute value of right arrow over x | 93 | |
| 7462315624 | U Subscript s | .5k(x^2) | 94 | |
| 7462322672 | Special P | m/V | 95 | |
| 7462349354 | A | Amplitude Alpha | 96 | |
| 7462354758 | E | Energy Echo | 97 | |
| 7462358687 | I | Rotational inertia. Iodine |  | 98 |
| 7462372373 | k | Spring constant. Kilo | 99 | |
| 7462387678 | l | Length | 100 | |
| 7462396093 | T | Period, temperature, Tango, and Thymine. | 101 | |
| 7462899336 | U | Potential energy and Uranium. |  | 102 |
| 7462912870 | V | Volume, Vanadium, five, and Victor. | 103 | |
| 7462935819 | v | Speed | 104 | |
| 7462939733 | y | Height |  | 105 |
| 7462957948 | Right Arrow Over Special A | (Sum of right arrow over Special T) over I | 106 | |
| 7462981924 | (Sum of Right Arrow Over Special T) Over I | ((Right arrow over Special T) subscript (net)) over I | 107 | |
| 7463004323 | Special A | Angular acceleration. | 108 | |
| 7463012747 | Coefficient of Friction | The ratio of the force of friction to the normal force acting between two objects. Number that serves as an index of the interaction between two surfaces in contact. |  | 109 |
| 7463040847 | (Change in U) Subscript g | mg(Change in y) | 110 | |
| 7463057582 | T Subscript s | 2 pi times the square root of (m/k) | 111 | |
| 7463078352 | T Subscript p | 2 pi times the square root of (l/g) | 112 | |
| 7463089173 | Absolute Value of (Right Arrow Over F Subscript g) | G times (m(1)m(2) over (r^2)) | 113 | |
| 7463107088 | Right Arrow Over g | (Right arrow over F subscript g) over m | 114 | |
| 7463122108 | U Subscript G | -((Gm(1)m(2)) over r) | 115 | |
| 7463142631 | Mechanics | The study of motion. The branch of physics that addresses the effects of forces on matter. |  | 116 |
| 7463146426 | Delta x | Change in x (Average velocity) times time | 117 | |
| 7463171371 | If Initial Velocity is equal to Final Velocity for t... | (Change in x) = (constant velocity) times time | 118 | |
| 7463182105 | Electricity | The flow of electrons. A form of energy caused by the movement of electrons. |  | 119 |
| 7463193426 | Absolute Value of (Right Arrow Over F Subscript E) | k times absolute value of ((q(1)q(2)) over r^2) | 120 | |
| 7463215999 | R | (Special P times l) over A Right | 121 | |
| 7463227514 | R Subscript s | Initial sum of initial R | 122 | |
| 7463279217 | 1 Over (R Subscript p) | Initial sum of (1 over initial R) | 123 | |
| 7463299035 | q | Charge | 124 | |
| 7463310064 | Waves | Disturbance that carries energy not matter. Any disturbance that transmits energy through matter or space. | 125 | |
| 7463322174 | Wavelength | v/f Horizontal distance between the crests or between the troughs of two adjacent waves. | 126 | |
| 7463351933 | Geometry | The branch of mathematics involving points, lines, planes, and figures. The study of shapes, angles, and etc. |  | 127 |
| 8549803874 | Impulse | J Change in momentum. |  | 128 |
| 8549808236 | J | (Average Force) times (Change in Time). Joule Ft | 129 | |
| 8549825816 | Ft | Ns Impulse | 130 | |
| 8549832078 | Momentum | p The product of an object's mass and velocity. |  | 131 |
| 8549835911 | mv | kgm/s Momentum | 132 | |
| 8549846158 | How could a person of mass 10m have the same momentum as a car of mass 2111m? | The person is traveling 211.1 times faster. (Mass of Person) times (Velocity of Person) = (Mass of Car) times (Velocity of Car) | 133 | |
| 8549862929 | How do momentum and impulse units relate to one another? | Ns = kgm/s = J = p Sum of Forces = ma Sum of Forces = m(Change in Velocity) / (Change in Time) (Sum of Forces)(Change in Time) = m(Change in Velocity) J = Change in Momentum Impulse = Change in Momentum | 134 | |
| 8549897289 | System | An object or group of objects whose motion is being tracked. An "isolated system" means there is no net external force that affects the motion. There can definitely be forces within the system. |  | 135 |
| 8556409873 | Isolated System | A system that exchanges neither matter nor energy with its surroundings. A closed system on which the net external force is zero. | 136 | |
| 8549903969 | Net External Force | Forces outside the system. The total force resulting from a combination of external forces on an object. |  | 137 |
| 8549907833 | Forces within the System | Action-Reaction forces. | 138 | |
| 8550147101 | (Initial Momentum of Object 1) + (Initial Momentum of Object 2) | (Final Momentum of Object 1) + (Final Momentum of Object 2) | 139 | |
| 8550159108 | (Mass of Object 1) times (Initial Velocity of Object 1) + (Mass of Object 2) times (Initial Velocity of Object 2) | (Mass of Object 1) times (Final Velocity of Object 1) + (Mass of Object 2) times (Final Velocity of Object 2) |  | 140 |
| 8550170883 | Sum of Forces | m(Change in Velocity) / (Change in Time) = (m(Final Velocity of Object) - m(Initial Velocity)) / (Change in Time) ((Final Momentum) - (Initial Momentum)) / (Change in Time) = (Change in Momentum) / (Change in Time) | 141 | |
| 8550201692 | (Sum of Forces) times (Change in Time) | Change in Momentum | 142 | |
| 8550206002 | If the System is not Isolated... | External forces act on the system. Use the impulse-momentum equation: (Change in Momentum) = Force times (Change in Time) | 143 | |
| 8550217680 | Change in Momentum | Force times (Change in Time) | | 144 |
| 8550235714 | How to Derive the Relationship between Impulse and Momentum from Newton's 2nd Law | Sum of Forces = ma Sum of Forces = m(Change in Velocity) / (Change in Time) (Sum of Forces) times (Change in Time) = m(Change in Velocity) J = Change in Momentum | 145 | |
| 8550257252 | Center of Mass | com A point in a system that moves as though all the mass is concentrated there and any external forces are applied there. |  | 146 |
| 8550262743 | Position Center of Mass | (((Mass of Object 1) times (Position of Object 1) + (Mass of Object 2) times (Position of Object 2) + (Mass of Object 3) times (Position of Object 3)) ...) / (((Mass of Object 1) + (Mass of Object 2) + (Mass of Object 3)) ...) |  | 147 |
| 8550286075 | Velocity Center of Mass | (((Mass of Object 1) times (Velocity of Object 1) + (Mass of Object 2) times (Velocity of Object 2) + (Mass of Object 3) times (Velocity of Object 3)) ...) / (((Mass of Object 1) + (Mass of Object 2) + (Mass of Object 3)) ...) |  | 148 |
| 8550295064 | Acceleration Center of Mass | (((Mass of Object 1) times (Acceleration of Object 1) + (Mass of Object 2) times (Acceleration of Object 2) + (Mass of Object 3) times (Acceleration of Object 3)) ...) / (((Mass of Object 1) + (Mass of Object 2) + (Mass of Object 3)) ...) |  | 149 |
| 8550305924 | How are all com equations related to one another? | They have the same form. All equations have terms added together and divided by total mass. | 150 | |
| 8550318941 | Three masses, Mass 1, Mass 2, and Mass 3, are in a line. Mass 1 of mass 10m is a distance 10x away from Mass 2 of mass 3m, which is a distance 3x away from Mass 3 of mass 4m. What is the COM of the three masses? Mass 1 is at the origin. Mass 2 is 10x distance in the positive direction from the origin. Mass 3 is 13x distance in the positive direction from the origin. | Position Center of Mass = (0 + 30mx + 52mx) / (10m + 3m + 4m) Position Center of Mass = 82mx / 17m Position Center of Mass = 4.823529412x or (82x / 17) | 151 | |
| 8554674042 | COM | Center of mass or center of motion. | 152 | |
| 8554674040 | A 4 kg mass is 2.1 m away from a wall and an 8 kg mass is 22 m away from a wall. What is the COM of the two masses? The origin is the wall and the objects are in the positive direction. | Position Center of Mass = (8.4 kgm + 176 kgm) / 12 kg Position Center of Mass = 184.4 kgm / 12 kg Position Center of Mass = 15.37 m or (461 m / 30) | 153 | |
| 8554711619 | Two people stand facing each other, and push off each other on roller skates. Person A has a mass of 4m and person B has a mass of 10m. If person A moves backward at 10v, determine the velocity of B. x is the unknown variable. | 4m times (-10v) + 10mx = 0 -40mv + 10mx = 0 10mx = 40mv x = 4v | 154 | |
| 8554733411 | Two people stand facing each other, and push off each other on roller skates. Person A has a mass of 4m and person B has a mass of 10m. If person A moves backward at 10v and person B moves forward at 4v, determine their change in momentum. | (Change in Momentum of Person A) = 4m times (Change in Velocity of Person A) (Change in Momentum of Person A) = 4m(-10v) (Change in Momentum of Person A) = -40mv (Change in Momentum of Person A) = -(Change in Momentum of Person B) (Change in Momentum of Person B) = 40mv | 155 | |
| 8554753401 | Two people stand facing each other, and push off each other on roller skates. Person A has a mass of 4m and person B has a mass of 10m. Person A moves backward at 10v and person B moves forward at 4v. If the change in momentum of person A is the opposite of the change in momentum of person B, determine the velocity of the center of mass before the collision. | Since the initial velocity of both objects was zero, the velocity center of mass before the collision was zero. | 156 | |
| 8554779011 | Two people stand facing each other, and push off each other on roller skates. Person A has a mass of 4m and person B has a mass of 10m. Person A moves backward at 10v and person B moves forward at 4v. The change in momentum of person A is the opposite of the change in momentum of person B. If the velocity of the center of mass before the collision was zero, determine the velocity center of mass after the collision. | Zero (Initial Velocity Center of Mass) = (Final Velocity Center of Mass) | 157 | |
| 8554785995 | What general principle is used for finding the unknown velocity in a collision? | Conservation of momentum. | 158 | |
| 8554794382 | After a collision, how do the change in momenta compare? | Equal and opposite. | 159 | |
| 8554798819 | What is the general principle of the velocity center of mass in a collision? | (Initial Velocity Center of Mass) = (Final Velocity Center of Mass) | 160 | |
| 8554810670 | Person A has a mass of 4m and is moving at speed 4v East, and person B has a mass of 10m and is moving at speed 10v East. After they collide, person B moves at a speed 3v East. Determine the velocity of A. x is the unknown variable. | 16mv + 100mv = 4mx + 30mv 116mv = 4mx + 30mv 86mv = 4mx 21.5v or (43v / 2) = x | 161 | |
| 8554840104 | Person A has a mass of 4m and is moving at speed 4v East, and person B has a mass of 10m and is moving at speed 10v East. After they collide, person B moves at a speed 3v East and person A moves at a velocity of 21.5v or (43v / 2) East. Determine their change in momentum. | (Change in Momentum of Person A) = 4m times (Change in Velocity of Person A) (Change in Momentum of Person A) = 4m(21.5v - 4v) (Change in Momentum of Person A) = 4m(17.5v) (Change in Momentum of Person A) = 70mv (Change in Momentum of Person A) = -(Change in Momentum of Person B) (Change in Momentum of Person B) = -70mv | 162 | |
| 8554917494 | Person A has a mass of 4m and is moving at speed 4v East, and person B has a mass of 10m and is moving at speed 10v East. After they collide, person B moves at a speed 3v East and person A moves at a velocity of 21.5v or (43v / 2) East. The change in momentum of person A is the opposite of the change in momentum of person B. Determine the velocity of the center of mass before the collision. | Initial Velocity Center of Mass = (16mv + 100mv) / (4m + 10m) Initial Velocity Center of Mass = 116mv / 14m Initial Velocity Center of Mass = 8.285714286v or (58v / 7) | 163 | |
| 8554979330 | Person A has a mass of 4m and is moving at speed 4v East, and person B has a mass of 10m and is moving at speed 10v East. After they collide, person B moves at a speed 3v East and person A moves at a velocity of 21.5v or (43v / 2) East. The change in momentum of person A is the opposite of the change in momentum of person B and the velocity of the center of mass before the collision is 8.285714286v. Determine the velocity center of mass after the collision. | 8.285714286v (Initial Velocity Center of Mass) = (Final Velocity Center of Mass) | 164 | |
| 8554996507 | What is the similarity between elastic and inelastic collisions? | Momentum is conserved. | 165 | |
| 8555003354 | What are the differences between elastic and inelastic collisions? | The type of collision, terminology, and whether or not kinetic energy is conserved. |  | 166 |
| 8555015760 | Completely Elastic Collisions | The objects don't stick together and when they collide their total initial kinetic and potential energies equals their total final kinetic and potential energies. This means that none of their energy is changed into thermal or heat energy. This type of collision is technically not possible because some energy always changes into thermal energy. But, some collisions can approximate this situation. |  | 167 |
| 8555038930 | Collision that can Approximate a Completely Elastic Collision | Two steel balls colliding. | 168 | |
| 8555041623 | Two Steel Balls Colliding | They don't deform much on impact and there is low friction between the balls and surfaces. | 169 | |
| 8555048976 | Inelastic Collisions | The objects may or may not stick together. Objects collide and become altered and generate heat during the collision. |  | 170 |
| 8555054371 | Examples of Inelastic Collisions | Two cars collide and they may or may not end up together but the cars get bent and there is friction between the tires and road. A ball bounces off a floor and doesn't bounce back to its original height. |  | 171 |
| 8555124547 | Terminology of Completely Elastic Collisions | The same as an elastic collision. | 172 | |
| 8555127899 | Elastic Collision | The objects in the system have 100% of their kinetic energy after collision. KE is conserved and objects bounce off with the same total speed they had before in different directions. | | 173 |
| 8555142434 | Terminology of Inelastic Collisions | A collision with anything less than 100% of the energy the same after collision. | 174 | |
| 8555149954 | Completely Inelastic Collision | Objects in the system have 0% of their kinetic energy after collision. |  | 175 |
| 8555162226 | Is momentum conserved in both elastic and inelastic collisions? | Yes because the sum of initial momenta is equal to the sum of final momenta, if there are no external forces on the system. | 176 | |
| 8555172845 | Is kinetic energy conserved in completely elastic collisions? | Yes because the sum of initial kinetic energy is equal to the sum of final kinetic energy because there is no thermal energy from friction. |  | 177 |
| 8555192853 | no | Not or opposite of yes. |  | 178 |
| 8555186571 | Is kinetic energy conserved in inelastic collisions? | No because the sum of initial kinetic energy is greater than the sum of final kinetic energy because there is thermal energy from friction. | 179 | |
| 8555204796 | Is a tennis ball dropped onto the floor a collision closer to a completely elastic collision or to a completely inelastic collision? | A completely elastic collision. | 180 | |
| 8555213458 | Is a hard steel ball dropped onto a hard metal object on the floor a collision closer to a completely elastic collision or to a completely inelastic collision? | A completely inelastic collision. | 181 | |
| 8555230513 | Is a hard rubber ball dropped onto a hard metal object on the floor a collision closer to a completely elastic collision or to a completely inelastic collision? | A completely elastic collision. | 182 | |
| 8555238827 | What is a force over time graph useful for? | If mass and initial velocity are known, the impulse can be used to calculate the instantaneous velocity at different times. | 183 | |
| 8555256832 | A car going at some speed 10v hits a tree. How does a seatbelt and/or airbag help a person survive in terms of the impulse-momentum equation? | They extend the amount of time that the force of impact is applied to the person, essentially lowering the impulse to less force per second. The momentum cannot be changed, but lowering the average force puts less stress on the person. | 184 | |
| 8555282592 | Cart 1 of mass 10m moving East at speed 10v collides with cart 2 or mass 3m moving West at 10v in a perfectly elastic collision. Calculate the objects' velocities after collision. | (Final Velocity of Cart 1) = (Mass of Cart 2) / (Mass of Cart 1) times (Initial Speed of Cart 2) (Final Velocity of Cart 1) = 3m / 10m times 10v (Final Velocity of Cart 1) = 3v (Final Velocity of Cart 2) = (Mass of Cart 1) / (Mass of Cart 2) times (Initial Speed of Cart 1) (Final Velocity of Cart 2) = 10m / 3m times 10v (Final Velocity of Cart 1) = 33.3v or (100v / 3) Cart 1 has a final velocity of 3v West and cart 2 has a final velocity of 33.3v or (100v / 3) East because in a perfectly elastic collision, if both objects are in motion opposite of each other, objects' velocities after collision are in the opposite direction of each objects original direction of motion. | 185 | |
| 8555355718 | General Principles of a Perfectly Elastic Collision | Conservation of momentum, equal and opposite, and initial velocity center of mass is equal to final velocity center of mass. | 186 | |
| 8555382334 | Work | W Force x Distance |  | 187 |
| 8555537698 | Energy Added to a System or Removed from a System by an Object that is not Part of the System | W | 188 | |
| 8555546334 | Fd | J W=__ |  | 189 |
| 8555552090 | Change in Distance | Displacement | | 190 |
| 8555557132 | Force x Displacement | Joules | 191 | |
| 8555560807 | Joules | Nm Unit of energy. |  | 192 |
| 8555567603 | If a mass 10m is lifted distance 10d and lowered a distance 10d, what is the net work against gravity? | Zero W = F times (Change in Distance) W = Fd + F(-d) W = 0 | 193 | |
| 8555578821 | Kinetic Energy | K = .5mv^2 Energy of motion. Energy a moving object has. J = kgm^2/s^2 |  | 194 |
| 8555580417 | If a mass 10m is moved at a constant speed a distance 10d to the right and then 10d to the left, and the coefficient of friction is mu, what is the net work against friction? | 20 Fd W = F times (Change in Distance) W = F(10d) + (-F)(-10d) W = 10Fd + 10Fd | 195 | |
| 8555623617 | Impulse-Momentum Relationship | Impulse is equal to the change in momentum of the object that the impulse acts on. The impulse that acts on an object is equal to the change in momentum of the object. |  | 196 |
| 8555638983 | Initial Velocity | The starting velocity. The velocity of the object before acceleration causes a change. | 197 | |
| 8555646496 | Final Velocity | (Original Velocity) + (Acceleration x Time) Velocity of an object at the end of a time interval. | 198 | |
| 8555651450 | vs. | Versus or against. |  | 199 |
| 8555659857 | y-Intercept | A point (0, b) where the line intersects the y-axis. The y-coordinate of a point where a graph crosses the y-axis. |  | 200 |
| 8555681250 | Mass | The amount of matter in an object. A measure of the amount of matter in an object. m |  | 201 |
| 8555684787 | Before | Initial Pre | 202 | |
| 8555711464 | After | Final Post | 203 | |
| 8555713698 | Vectors | Quantities that have both a magnitude and a direction. Quantities that are fully described by both a magnitude and a direction. |  | 204 |
| 8555745122 | Velocity-Time Graph | Plot of velocity of object as a function of time. Shows how velocity is related to time. | | 205 |
| 8555802116 | Projectile Motion | The curved path an object follows when thrown or propelled near the surface of the Earth. The curved path of an object in free fall after it is given an initial forward velocity. |  | 206 |
| 8555807452 | Newton's Laws | Laws governing motion. Laws proposed by Isaac Newton that explain how force and motion work. |  | 207 |
| 8555759859 | Is it true that an object moving at a constant speed must have no forces acting on it? | No | 208 | |
| 8555774568 | Action-Reaction Forces | For every action, there is an equal and opposite reaction. If 50 N is exerted to the right, then 50 N will be reacted to the left. |  | 209 |
| 8555779243 | Friction Force | Force that opposes motion of an object when two surfaces are in contact. The force exerted by a surface as an object moves across it or makes an effort to move across it. |  | 210 |
| 8555789703 | Weight | A measure of the force of gravity on an object. A measure of the gravitational force exerted on an object. |  | 211 |
| 8555792641 | Normal Forces | Support forces perpendicular force of floor on object. The force of 'the ground.' This force holds objects up from falling to the center of the earth. | 212 | |
| 8555813027 | FBDs | Free Body Diagrams. |  | 213 |
| 8555815589 | Sigma F | Sum of Force. | 214 | |
| 8555824845 | Would there be less friction when pushing an object at an angle below the horizontal or pulling an object at an angle above the horizontal? | Pulling an object at an angle above the horizontal. | 215 | |
| 8555844583 | FBD | Free Body Diagram. | | 216 |
| 8555847414 | Force of Tension | Always a pulling force through a rope or string, etc. |  | 217 |
| 8555850749 | mu | Coefficient of friction. む | 218 | |
| 8555856703 | Friction | A force that opposes motion between two surfaces that are in contact. The resistance that one surface or object encounters when moving over another. |  | 219 |
| 8555863912 | Tension | Stress that stretches rock so that it becomes thinner in the middle. A force that pulls on a material. | | 220 |
| 8555883376 | A 71.1 kg cyclist rides at 3.11 rpm around a flat 41.1 m circular track. Calculate the cyclist's frequency. | Frequency = 3.11 rpm / 60 s Frequency = .05183 Hz or (311 Hz / 6000) | 221 | |
| 8556283533 | A 71.1 kg cyclist rides at 3.11 rpm around a flat 41.1 m circular track and the cyclist's frequency is .05183 Hz. Calculate the cyclist's period. | Period = 1 / Frequency Period = (6000 Hz / 311) or 19.2926045 s | 222 | |
| 8556313369 | A 71.1 kg cyclist rides at 3.11 rpm around a flat 41.1 m circular track . The cyclist's frequency is .05183 Hz and has a period of 19.2926045 s. Calculate the cyclist's velocity. | Velocity = Distance / Time Velocity = 2 x pi x r / Period Velocity = 2pi41.1m / 19.2926045 s Velocity = 258.2389161 m / 19.2926045 s Velocity = 13.38538382 m / s | 223 | |
| 8556355788 | A 71.1 kg cyclist rides at 3.11 rpm around a flat 41.1 m circular track . The cyclist's frequency is .05183 Hz, has a period of 19.2926045 s, and has a velocity of 13.38538382 m / s. Calculate the cyclist's acceleration. | Acceleration = v^2 / r Acceleration = (13.38538382 m / s)^2 / 41.1 m Acceleration = 179.1685 m^2 / s^2 / 41.1 m Acceleration = 4.3593309 m / s^2 | 224 | |
| 8556398050 | rpm | The abbreviation for "revolutions per minute," which measures the rotation speed of audio recordings or an object moving in a circular or periodical pattern. |  | 225 |
| 8556407584 | Revolutions per Minute | A unit of rotational speed. It is symbolized as rpm. |  | 226 |
| 8556398049 | Frequency | How many wave peaks pass a certain point per given time. The number of complete wavelengths that pass a point in a given time. | 227 | |
| 8556418450 | Period | A horizontal row of elements in the periodic table. A length or portion of time. | 228 | |
| 8556420554 | Newton's Law of Gravitation | Gravitational pull of an object by another; GMm/(r*r)=mg |  | 229 |
| 8556433123 | Gravity | A force of attraction between objects that is due to their masses. A force that pulls objects toward each other. |  | 230 |
| 8556442372 | Planet X has a radius 10r. A satellite is launched from the surface and moves out to an altitude of 11r. Calculate the change in gravity. | Initial Force of Gravity = G(Mass of Planet X)(Mass of Satellite) / r^2 Initial Force of Gravity = G(Mass of Planet X)(Mass of Satellite) / (10^2)r Initial Force of Gravity = G(Mass of Planet X)(Mass of Satellite) / 100r Final Force of Gravity = G(Mass of Planet X)(Mass of Satellite) / r^2 Final Force of Gravity = G(Mass of Planet X)(Mass of Satellite) / (11^2)r Final Force of Gravity = G(Mass of Planet X)(Mass of Satellite) / 121r 1 / 100 = 1 / 121 100 / 121 = .826446281 or (100 : 121) | 231 | |
| 8556485417 | Planet X has a radius 10r. A satellite is launched from the surface and moves out to an altitude of 11r. The change in gravity is .826446281. Calculate the change in satellite velocity. | Initial Velocity = Distance / Time Initial Velocity = 2 x pi x r / Period Initial Velocity = 2pi10r / Period Initial Velocity = 62.83185307r / Period or (417392r / 6643 Period) Final Velocity = Distance / Time Final Velocity = 2 x pi x r / Period Final Velocity = 2pi11r / Period Final Velocity = 69.11503838r / Period 69.11503838r - 62.83185307r = 6.283185301 m/s | 232 | |
| 8556530213 | Planet X has a radius 10r. A satellite is launched from the surface and moves out to an altitude of 11r. The change in gravity is .826446281 or 100 : 121. The change in satellite velocity is +6.283185301 m / s. Calculate the change in satellite period. | Change in Satellite Period = 69.11503838r / Period / (62.83185307r / Period) Change in Satellite Period = 1.1 or (11 : 10) | 233 | |
| 8556558838 | What is the meaning of the term of conservation in laws like momentum or energy or mass or charge conservation? | None is lost. The initial total is the final total. | 234 | |
| 8556545883 | Energy | The ability to do work or cause change. The capacity to do work. | | 235 |
| 8556615340 | What is true of the velocity of the center of mass in a collision? | Stays the same. | 236 | |
| 8556619299 | What is true of the change in momenta of two objects colliding? | Equal and opposite. | 237 | |
| 8556627170 | Is momentum always conserved? | In theory. In reality, some kinetic energy is always lost to thermal energy. | 238 | |
| 8556640717 | A bullet of mass 10m is moving East at speed 611v hits a wood block of mass 2111m moving West at 3v on a frictionless table. If the bullet is embedded in the block, calculate its velocity after impact. x is the unknown variable. | 10m611v + 2111m(-3v) = 2121mxv 6110mv - 6333mv = 2121mvx -223mv = 2121mvx -.1051390853v or (-223v / 2121) = x The bullet and wood block would have a velocity of .1051390853v or (-223v / 2121) West because West is the negative direction and the momentum of the wood block was larger than the momentum of the bullet. | 239 | |
| 8556698594 | A bullet of mass 10m is moving East at speed 611v hits a wood block of mass 2111m moving West at 3v on a frictionless table. If the bullet is embedded in the block and its velocity is .1051390853v West, calculate the velocity of the center of mass. x is the unknown variable. | The velocity center of mass is .1051390853v or (-223v / 2121) West because in this completely inelastic collision, the final velocity is the same as the velocity center of mass. | 240 | |
| 8556697139 | A bullet of mass 21m is moving East at speed 722v hits a wood block of mass 3222m moving West at 4v on a frictionless table. If the bullet passes through the block and exits East at 311v, calculate the block's velocity. x is the unknown variable. | 21m722v + 3222m4v = 21m311v + 3222mx 15162mv + 12888mv = 6531mv + 3222mx 28050mv = 6531mv + 3222mx 21519mv = 3222mx 6.67877095v or (2391v / 358) = x The wood block would have a velocity of 6.67877095v or (2391v / 358) East because East is the positive direction and the momentum of the bullet was larger than the momentum of the wood block. | 241 | |
| 8556760777 | A bullet of mass 21m is moving East at speed 722v hits a wood block of mass 3222m moving West at 4v on a frictionless table. If the bullet passes through the block and exits East at 311 and the velocity of the wooden block is 6.67877095v East, calculate the velocity of the center of mass. x is the unknown variable. | (Velocity of the Center of Mass) = 28050mv / (21m + 3222m) (Velocity of the Center of Mass) = 28050mv / 3242m (Velocity of the Center of Mass) = 8.649398705v | 242 | |
| 8556792137 | A ball of mass 3m and moving East at 10v collides with a ball of mass 4m at rest. If the collision is completely elastic and they don't stick together, what principle(s) is/are used to determine their velocities after collision? | Conservation of momentum. | 243 | |
| 8556795652 | A ball of mass 3m and moving East at 10v collides with a ball of mass 4m at rest. If the collision is completely elastic and they don't stick together, calculate their velocities after collision. | (Final Velocity of Ball 1) = 0 (Final Velocity of Ball 2) = 3m10v / 4m (Final Velocity of Ball 2) = 30mv / 4m (Final Velocity of Ball 2) = 7.5v or (15v / 2) | 244 |
