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Calculus AB Exam Flashcards

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382023814Intermediate Value TheoremIf f(1)=-4 and f(6)=9, then there must be a x-value between 1 and 6 where f crosses the x-axis.
382023815Average Rate of ChangeSlope of secant line between two points, use to estimate instantanous rate of change at a point.
382023816Instantenous Rate of ChangeSlope of tangent line at a point, value of derivative at a point
382023817Formal definition of derivativelimit as h approaches 0 of [f(a+h)-f(a)]/h
382023818Alternate definition of derivativelimit as x approaches a of [f(x)-f(a)]/(x-a)
382023819When f '(x) is positive, f(x) isincreasing
382023820When f '(x) is negative, f(x) isdecreasing
382023821When f '(x) changes from negative to positive, f(x) has arelative minimum
382023822When f '(x) changes fro positive to negative, f(x) has arelative maximum
382023823When f '(x) is increasing, f(x) isconcave up
382023824When f '(x) is decreasing, f(x) isconcave down
382023825When f '(x) changes from increasing to decreasing or decreasing to increasing, f(x) has apoint of inflection
382023826When is a function not differentiablecorner, cusp, vertical tangent, discontinuity
382023827Product Ruleuv' + vu'
382023828Quotient Rule(uv'-vu')/v²
382023829Chain Rulef '(g(x)) g'(x)
382023830y = x cos(x), state rule used to find derivativeproduct rule
382023831y = ln(x)/x², state rule used to find derivativequotient rule
382023832y = cos²(3x)chain rule
382023833Particle is moving to the right/upvelocity is positive
382023834Particle is moving to the left/downvelocity is negative
382023835absolute value of velocityspeed
382023836y = sin(x), y' =y' = cos(x)
382023837y = cos(x), y' =y' = -sin(x)
382023838y = tan(x), y' =y' = sec²(x)
382023839y = csc(x), y' =y' = -csc(x)cot(x)
382023840y = sec(x), y' =y' = sec(x)tan(x)
382023841y = cot(x), y' =y' = -csc²(x)
382023842y = sin⁻¹(x), y' =y' = 1/√(1 - x²)
382023843y = cos⁻¹(x), y' =y' = -1/√(1 - x²)
382023844y = tan⁻¹(x), y' =y' = 1/(1 + x²)
382023845y = cot⁻¹(x), y' =y' = -1/(1 + x²)
382023846y = e^x, y' =y' = e^x
382023847y = a^x, y' =y' = a^x ln(a)
382023848y = ln(x), y' =y' = 1/x
382023849y = log (base a) x, y' =y' = 1/(x lna)
382023850To find absolute maximum on closed interval [a, b], you must consider...critical points and endpoints
382023851mean value theoremif f(x) is continuous and differentiable, slope of tangent line equals slope of secant line at least once in the interval (a, b) f '(c) = [f(b) - f(a)]/(b - a)
382023852If f '(x) = 0 and f"(x) > 0,f(x) has a relative minimum
382023853If f '(x) = 0 and f"(x) < 0,f(x) has a relative maximum
382023854Linearizationuse tangent line to approximate values of the function
382023855ratederivative
382023856left riemann sumuse rectangles with left-endpoints to evaluate integral (estimate area)
382023857right riemann sumuse rectangles with right-endpoints to evaluate integrals (estimate area)
382023858trapezoidal ruleuse trapezoids to evaluate integrals (estimate area)
382023859[(h1 - h2)/2]*basearea of trapezoid
382023860definite integralhas limits a & b, find antiderivative, F(b) - F(a)
382023861indefinite integralno limits, find antiderivative + C, use inital value to find C
382023862area under a curve∫ f(x) dx integrate over interval a to b
382023863area above x-axis ispositive
382023864area below x-axis isnegative
382023865average value of f(x)= 1/(b-a) ∫ f(x) dx on interval a to b
382023866If g(x) = ∫ f(t) dt on interval 2 to x, then g'(x) =g'(x) = f(x)
382023867Fundamental Theorem of Calculus∫ f(x) dx on interval a to b = F(b) - F(a)
382023868To find particular solution to differential equation, dy/dx = x/yseparate variables, integrate + C, use initial condition to find C, solve for y
382023869To draw a slope field,plug (x,y) coordinates into differential equation, draw short segments representing slope at each point
382023870slope of horizontal linezero
382023871slope of vertical lineundefined
382023872methods of integrationsubstitution, parts, partial fractions
382023873use substitution to integrate whena function and it's derivative are in the integrand
382023874use integration by parts whentwo different types of functions are multiplied
382023875∫ u dv =uv - ∫ v du
382023876use partial fractions to integrate whenintegrand is a rational function with a factorable denominator
382023877dP/dt = kP(M - P)logistic differential equation, M = carrying capacity
382023878P = M / (1 + Ae^(-Mkt))logistic growth equation
382023879given rate equation, R(t) and inital condition when t = a, R(t) = y₁ find final value when t = by₁ + Δy = y Δy = ∫ R(t) over interval a to b
382023880given v(t) and initial position t = a, find final position when t = bs₁+ Δs = s Δs = ∫ v(t) over interval a to b
382023881given v(t) find displacement∫ v(t) over interval a to b
382023882given v(t) find total distance travelled∫ abs[v(t)] over interval a to b
382023883area between two curves∫ f(x) - g(x) over interval a to b, where f(x) is top function and g(x) is bottom function
382023884volume of solid with base in the plane and given cross-section∫ A(x) dx over interval a to b, where A(x) is the area of the given cross-section in terms of x
382023885volume of solid of revolution - no washerπ ∫ r² dx over interval a to b, where r = distance from curve to axis of revolution
382023886volume of solid of revolution - washerπ ∫ R² - r² dx over interval a to b, where R = distance from outside curve to axis of revolution, r = distance from inside curve to axis of revolution
382023887length of curve∫ √(1 + (dy/dx)²) dx over interval a to b
382023888L'Hopitals ruleuse to find indeterminate limits, find derivative of numerator and denominator separately then evaluate limit
382023889sin^2 x + cos^2 x1
3820238901 + tan^2 xsec^2 x
3820238911 + cot^2 xcsc^2 x
382023892sin(-x)-sin x
382023893cos(-x)cos x
382023894tan(-x)-tan x
382023895sin(A + B)sin A cos B + sin B cos A
382023896sin(A - B)sin A cos B - sin B cos A
382023897cos(A + B)cos A cos B - sin A sin B
382023898cos(A - B)cos A cos B + sin A sin B
382023899sin 2x2 sin x cos x
382023900cos 2x (1)cos^2 x - sin^2 x
382023901cos 2x (2)2cos^2 x - 1
382023902cos 2x (3)1 - 2sin^2 x
382023903tan x1/ cot x
382023904cot x1/ tan x
382023905sec x1/ cos x
382023906csc x1/ sin x
382023907cos(pi/2 - x)sin x
382023908sin(pi/2 - x)cos x
382023909d/dx (x^n)nx^n - 1
382023910d/dx (fg)fg' + gf'
382023911d/dx (f/g)(gf' - fg')/g^2
382023912d/dx f(g(x))f'(g(x))g'(x)
382023913d/dx (sin x)cos x
382023914d/dx (cos x)- sin x
382023915d/dx (tan x)sec^2 x
382023916d/dx (cot x)- csc^2 x
382023917d/dx (sec x)sec x tan x
382023918d/dx (csc x)-csc x cot x
382023919d/dx (e^x)e^x
382023920d/dx (a^x)a^x ln a
382023921d/dx (ln x)1/x
382023922d/dx (Arcsin x)1/(sqrt(1 - x^2))
382023923d/dx (Arctan x)1/(1 + x^2)
382023924∫ a dxax + c
382023925∫ 1/x dxln | x | + c
382023926∫ e^x dse^x + c
382023927∫ a^x dxa^x/ ln a + c
382023928∫ ln x dxx ln x - x + c
382023929∫ sin x dx-cos x + c
382023930∫ cos x dxsin x + c
382023931∫ tan x dx (1)ln |sec x| + c
382023932∫ tan x dx (2)-ln |cos x| + c
382023933∫ cot x dxln |sin x| + c
382023934∫ sec x dxln |sec x + tan x| + c
382023935∫ csc x dx-ln |csc x + cot x| + c
382023936∫ sec^2 x dxtan x + c
382023937∫ sec x tan x dxsec x + c
382023938∫ csc^2 x dx- cot x + c
382023939∫ csc x cot x dx- csc x + c
382023940∫ tan^2 x dxtan x - x + c
382023941∫ dx/(a^2 + x^2)1/a Arctan (x/a) + c
382023942∫ dx/(sqrt(a^2 - x^2))Arcsin (x/a) + c

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