AP Notes, Outlines, Study Guides, Vocabulary, Practice Exams and more!
Mercury and bromine will react with each other to produce mercury(II) bromide.
Hg(l) + Br2(l) HgBr2(s)
(a) What mass of HgBr2 can be produced from the reaction of 10.15 g Hg and 8.89 g Br2?
What mass of reagent is left unreacted?
Which reagent is in excess?
Br2 or Hg
(b) What mass of HgBr2 can be produced from the reaction of 6.95 mL mercury (density = 13.6 g/mL) and 6.95 mL bromine (density = 3.10 g/mL)?
help me...T.T:eek:
We hope your visit has been a productive one. If you're having any problems, or would like to give some feedback, we'd love to hear from you.
For general help, questions, and suggestions, try our dedicated support forums.
If you need to contact the Course-Notes.Org web experience team, please use our contact form.
While we strive to provide the most comprehensive notes for as many high school textbooks as possible, there are certainly going to be some that we miss. Drop us a note and let us know which textbooks you need. Be sure to include which edition of the textbook you are using! If we see enough demand, we'll do whatever we can to get those notes up on the site for you!
Ah, stoicheometry. This may take awhile....
I'll come back later...
[=RoyalBlue][=Comic Sans MS]
"I refuse to prove that I exist," says God, "for proof denies faith, and without faith I am nothing."
"But," say Man, "the Babel fish is a dead giveaway, isn't it? It could not have evolved by chance. It
For the first, I think you have to calculate which element is the limiting reactant, then use that in your stoich. equation. Divide the amount of LR used in the reaction by its molar mass, then multiply by the mole/mole ratio (multiply by # of moles of LR, divide by # moles of HgBr2), then multiply by the molar mass of HgBr2. I think the initial LR calculation should tell you how much of the excess reactent is left, and if you find the LR, you will know which is in excess. And for the last one, use the density of the liquid to convert the mL into grams, and do the stoich. equation from there. Have fun!
The hardest thing about riding horses is the ground
[CENTER][IMG]http://i29.photobucket.com/albums/c295/xenahorse/Photoshop%20Fun/Ed_Ein_...
[=1]Made by moi^:D[/
That sounds right. I'd write it all out for you rlaanrndghk, but everything kinda came down on me and I've been super busy. But xenahorse does a good job too.:D
[=RoyalBlue][=Comic Sans MS]
"I refuse to prove that I exist," says God, "for proof denies faith, and without faith I am nothing."
"But," say Man, "the Babel fish is a dead giveaway, isn't it? It could not have evolved by chance. It
Thank you! Now that my class is over, I finally remember how to do everything!
The hardest thing about riding horses is the ground
[CENTER][IMG]http://i29.photobucket.com/albums/c295/xenahorse/Photoshop%20Fun/Ed_Ein_...
[=1]Made by moi^:D[/
Thank you... xenahorse! You helped a lot! I will wait for other replys...!