conjugate acid-base pairs - HX + H2O >> X- + H3O+
- HX is acid
- conjugate acid of X- (add proton)
- H2O acts as base
- conjugate base of H3O+ (subtract proton)
- X- is base
- conjugate base of HX (subtract proton)
- H3O+ acts as acid
- conjugate acid of H2O (add proton)
- conjugate acid of strong base = weak acid
- conjugate acid of weak base = strong acid
- conjugate base of strong acid = weak base
- conjugate base of weak acid = strong base
- Ka x Kb = Kw
- Kw = 1.0 x 10-14 (water autoionizes)
- Ka = Kb >> neutral solution
Find the pH for 0.25 M of sodium lactate
- conjugate acid is lactic acid
- Ka of lactic acid = 1.4 x 10-4
- Kb = Kw / Ka = 10-14 / (1.4 x 10-4) = 7.14 x 10-11
- Kb = [OH-] [lactic acid] / [lactate]
- [OH-] = [(7.14 x 10-11) (0.25)]1/2 = 4.2 x 10-6
- pOH = -log [OH-] = 5.37
- pH = 14 - 5.37 = 8.63
hydrolysis - ability of ions to react w/ water to make H+, OH- ions
- anions act as bases (adding proton >> acid)
- identify conjugate acid, use Kw to find the strength
- anions of strong acids have negligible effect
- anions of weak acids increase pH
- cations act as acids (subtract proton >> base)
- identify conjugate base, use Kw to find the strength
- cations of strong bases have negligible effect
- cations of weak bases decrease pH