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The Early Cold War 1950-1960

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US History
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Post WWII – US Concerns “Spread of Communism” Or what happened to Uncle Joe? “Cold” War – how can it be??? WHY THE FEAR OF COMMUNISM? • Geography – areas of influence at end of WWII • Values of communism (as reflected in the Soviet Union) were incompatible with democracy and capitalism (free market economies) • Soviet Actions: o No free elections in eastern Europe (e.g., Poland 1945) o Soviets establish “satellite” countries in Eastern Europe (e.g., Poland) o Berlin Blockade/Airlift 1948 o Stalin’s “incompatibility speech” USSR to produce weapons rather than consumer goods o Soviet A-Bomb 1949!!!! America’s Reaction: • In 1946, George Kennan (US diplomat in Moscow) proposes policy of containment against the Soviet Union. Two parts:

Factor and Remainder Theorem

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Algebra
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Polynomials
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Polynomial
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Applied mathematics
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Factor and remainder theorem
Factor The expression x-a is a linear factor of a polynomial if and only if the value a is a zero related polynomial function. Remainder If a polynomial function P(x) of a degree greater than or equal to 1 is divided by the linear factor (x-a), where a is a constant, then the remainder is P(a)

Factor and Remainder Theorem

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Algebra
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Polynomials
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Applied mathematics
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Factor and remainder theorem
Factor The expression x-a is a linear factor of a polynomial if and only if the value a is a zero related polynomial function. Remainder If a polynomial function P(x) of a degree greater than or equal to 1 is divided by the linear factor (x-a), where a is a constant, then the remainder is P(a)

Solving Logarithmic Equations

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Calculus
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Digital media
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Calculus
logarithmic

he first type of logarithmic equation has two?logs, each having the same base, set equal to each other, and you solve by setting the insides (the "arguments") equal to each other. For example: Solve?log2(x) =?log2(14). Since the logarithms on either side of the equation have the same base ("2", in this case), then the only way these two logs can be equal is for their arguments to be equal. In other words, the log expressions being equal says that the arguments must be equal, so I have: x?= 14 And that's the solution:?x?= 14 Solve?logb(x2) =?logb(2x?? 1). Since the bases of the logs are the same (the unknown value "b", in this case), then the insides must be equal. That is: x2?=?2x?? 1 Then I can solve the log equation by?solving this quadratic equation: x2?? 2x?+ 1 = 0
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